Exams/ece241 2014 q3

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For the following Karnaugh map, give the circuit implementation using one 4-to-1 multiplexer and as many 2-to-1 multiplexers as required, but using as few as possible. You are not allowed to use any other logic gate and you must use a and b as the multiplexer selector inputs, as shown on the 4-to-1 multiplexer below.

You are implementing just the portion labelled top_module, such that the entire circuit (including the 4-to-1 mux) implements the K-map.

Ece241 2014 q3.png

Ece241 2014 q3mux.png

(The requirement to use only 2-to-1 multiplexers exists because the original exam question also wanted to test logic function simplification using K-maps and how to synthesize logic functions using only multiplexers with constant inputs. If you wish to treat this as purely a Verilog exercise, you may ignore this constraint and write the module any way you wish.)

Module Declaration

module top_module (
    input c,
    input d,
    output [3:0] mux_in
); 

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